add more info about the answer

This commit is contained in:
filifa 2025-07-20 15:42:21 -04:00
parent 108be2b590
commit 82f06fae28
1 changed files with 68 additions and 15 deletions

View File

@ -43,7 +43,7 @@
"id": "431ef21c", "id": "431ef21c",
"metadata": {}, "metadata": {},
"source": [ "source": [
"Now we can just iterate through our new generator and count the perimeters. We also count multiples of the perimeters to include non-primitive triplets." "Now we can just iterate through our new generator and group each triangle by their perimeters. We also multiply to consider non-primitive triplets."
] ]
}, },
{ {
@ -53,6 +53,34 @@
"metadata": { "metadata": {
"scrolled": true "scrolled": true
}, },
"outputs": [],
"source": [
"max_perim = 1000\n",
"perimeters = dict()\n",
"for (a, b, c) in primitive_pythagorean_triplets(max_perim):\n",
" for k in count(1):\n",
" perimeter = k * (a + b + c)\n",
" if perimeter > max_perim:\n",
" break\n",
" \n",
" if perimeter not in perimeters:\n",
" perimeters[perimeter] = set()\n",
" perimeters[perimeter].add((k*a, k*b, k*c))"
]
},
{
"cell_type": "markdown",
"id": "f776a5c6",
"metadata": {},
"source": [
"Our answer is whichever perimeter has the highest total."
]
},
{
"cell_type": "code",
"execution_count": 3,
"id": "0cd6241f",
"metadata": {},
"outputs": [ "outputs": [
{ {
"data": { "data": {
@ -60,25 +88,50 @@
"840" "840"
] ]
}, },
"execution_count": 2, "execution_count": 3,
"metadata": {}, "metadata": {},
"output_type": "execute_result" "output_type": "execute_result"
} }
], ],
"source": [ "source": [
"from collections import Counter\n", "p = max(perimeters, key=lambda x: len(perimeters[x]))\n",
"\n", "p"
"max_perim = 1000\n", ]
"perimeters = Counter()\n", },
"for (a, b, c) in primitive_pythagorean_triplets(max_perim):\n", {
" for k in count(1):\n", "cell_type": "markdown",
" perimeter = k * (a + b + c)\n", "id": "f32fb164",
" if perimeter > max_perim:\n", "metadata": {},
" break\n", "source": [
" \n", "There are eight triangles with this perimeter."
" perimeters[perimeter] += 1\n", ]
"\n", },
"max(perimeters, key=perimeters.get)" {
"cell_type": "code",
"execution_count": 4,
"id": "9c31c68f",
"metadata": {},
"outputs": [
{
"data": {
"text/plain": [
"{(105, 360, 375),\n",
" (140, 336, 364),\n",
" (210, 280, 350),\n",
" (252, 240, 348),\n",
" (315, 168, 357),\n",
" (350, 120, 370),\n",
" (390, 56, 394),\n",
" (399, 40, 401)}"
]
},
"execution_count": 4,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [
"perimeters[p]"
] ]
}, },
{ {