add problem 28
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"cells": [
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"cell_type": "markdown",
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"id": "dee40daf",
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"metadata": {},
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"source": [
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"# [Number Spiral Diagonals](https://projecteuler.net/problem=28)\n",
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"\n",
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"Whether you choose to program or just use pen and paper, there's a lot of different ways to tackle this problem. Here's one approach.\n",
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"\n",
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"If we have an $n \\times n$ spiral (note that $n$ must be odd!), it's pretty easy to get a formula for just the sum of the corners. The top right corner will always be $n^2$, and since it's an $n \\times n$ spiral (as mentioned one sentence ago), the top left corner will just be $n^2 - (n - 1)$. We can continue subtracting $n-1$ to get the values of the other corners. Adding these up, we get\n",
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"$$f(n) = n^2 + (n^2 - (n-1)) + (n^2 - 2(n-1)) + (n^2 - 3(n-1)) = 4n^2 - 6n + 6$$\n",
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"\n",
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"Of course, we want the sums of the *diagonals*, not just the outermost corners. We can think about this as getting the sum of the corners of the $n \\times n$ spiral, plus the sum of the corners of the $(n-2) \\times (n-2)$ spiral one layer deeper, and so on until we reach the 1 at the center.\n",
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"$$g(n) = f(n) + f(n-2) + f(n-4) + \\cdots + f(5) + f(3) + 1 = 1 + \\sum_{k=1}^{(n-1)/2} f(2k + 1) = 1 + \\sum_{k=1}^{(n-1)/2} (16k^2 + 4k + 4)$$\n",
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"\n",
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"Now we can apply [summation identities](https://en.wikipedia.org/wiki/Summation) (including the return of triangular numbers and square pyramidal numbers from [problem 6](https://projecteuler.net/problem=6)) to get a closed formula:\n",
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"$$g(n) = \\frac{2}{3}n^3 + \\frac{1}{2}n^2 + \\frac{4}{3}n - \\frac{3}{2}$$\n",
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"Plugging in 1001, we get our answer: $g(1001) = 669171001$.\n",
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"\n",
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"Side note: this practice of writing the natural numbers in a spiral, combined with marking the prime numbers, has been coined the [Ulam spiral](https://en.wikipedia.org/wiki/Ulam_spiral). Somewhat interestingly, lots of primes appear in vertical, horiztonal, and diagonal lines when laid out this way.\n",
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"\n",
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"## Relevant sequences\n",
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"* Numbers on diagonals: [A200975](https://oeis.org/A200975)"
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]
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}
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],
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"display_name": "SageMath 9.5",
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"language": "sage",
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"name": "sagemath"
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},
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"language_info": {
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"codemirror_mode": {
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"name": "ipython",
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"version": 3
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},
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"file_extension": ".py",
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"mimetype": "text/x-python",
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"name": "python",
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"nbconvert_exporter": "python",
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"pygments_lexer": "ipython3",
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"version": "3.11.2"
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}
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"nbformat": 4,
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"nbformat_minor": 5
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}
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