97 lines
3.6 KiB
Plaintext
97 lines
3.6 KiB
Plaintext
{
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"cells": [
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{
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"cell_type": "markdown",
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"id": "dea82444",
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"metadata": {},
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"source": [
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"# [Amicable Numbers](https://projecteuler.net/problem=21)\n",
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"\n",
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"The sum of the proper divisors of a number is called the [aliquot sum](https://en.wikipedia.org/wiki/Aliquot_sum).\n",
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"\n",
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"SageMath [provides the `sigma` function](https://doc.sagemath.org/html/en/reference/rings_standard/sage/arith/misc.html#sage.arith.misc.Sigma), which can compute the sum of the divisors of $n$. The aliquot sum is then just `sigma(n) - n`.\n",
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"\n",
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"If a number is equal to its own aliquot sum, it's called a [perfect number](https://en.wikipedia.org/wiki/Perfect_number), and we exclude those numbers from our total."
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]
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},
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{
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"cell_type": "code",
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"execution_count": 1,
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"id": "144e1f54",
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"metadata": {},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"31626\n"
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]
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}
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],
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"source": [
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"aliquot_sum = lambda n: sigma(n) - n\n",
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"\n",
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"amicables = set()\n",
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"for a in range(2, 10000):\n",
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" if a in amicables:\n",
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" continue\n",
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" \n",
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" b = aliquot_sum(a)\n",
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" if a == b:\n",
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" continue\n",
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" \n",
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" if a == aliquot_sum(b):\n",
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" amicables.update({a, b})\n",
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"\n",
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"print(sum(amicables))"
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]
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},
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{
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"cell_type": "markdown",
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"id": "ca7d5f36",
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"metadata": {},
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"source": [
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"Funny enough, there's only five pairs of amicable numbers below 10,000. If you looked up [amicable numbers](https://en.wikipedia.org/wiki/Amicable_numbers), you may have stumbled on all the numbers you need to answer the problem!\n",
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"\n",
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"## Sum of divisors\n",
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"Of course, you could implement your own [divisor sum function](https://en.wikipedia.org/wiki/Divisor_function). In [problem 12](https://projecteuler.net/problem=12), we implemented a divisor *counting* function, which is related.\n",
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"\n",
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"One important property of the divisor sum function $\\sigma(n)$ is that it is [multiplicative](https://en.wikipedia.org/wiki/Multiplicative_function). This means that if $a$ and $b$ are [coprime](https://en.wikipedia.org/wiki/Coprime_integers), $\\sigma(ab) = \\sigma(a)\\sigma(b)$. It follows that if $n = 2^{r_1}3^{r_2}5^{r_3}7^{r_4}\\cdots$, then\n",
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"$$\\sigma(n) = \\sigma(2^{r_1})\\sigma(3^{r_2})\\sigma(5^{r_3})\\sigma(7^{r_4})\\cdots$$\n",
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"\n",
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"Furthermore, for a prime $p$, $\\sigma(p^k) = 1 + p + p^2 + \\cdots + p^k$. This expression is actually a partial sum of a [geometric series](https://en.wikipedia.org/wiki/Geometric_series), which has a closed formula:\n",
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"$$1 + p + p^2 + \\cdots + p^k = \\frac{p^{k+1}-1}{p-1}$$\n",
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"\n",
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"Putting it all together, we can compute $\\sigma(n)$ as\n",
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"$$\\sigma(n) = \\frac{2^{r_1+1}-1}{2-1} \\cdot \\frac{3^{r_2+1}-1}{3-1} \\cdot \\frac{5^{r_3+1}-1}{5-1} \\cdot \\frac{7^{r_4+1}-1}{7-1} \\cdot \\cdots$$\n",
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"\n",
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"Therefore, if you have the number's factorization (see [problem 3](https://projecteuler.net/problem=3)), you can use it to compute the sum of its divisors.\n",
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"\n",
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"## Relevent sequences\n",
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"* Amicable numbers: [A063990](https://oeis.org/A063990)"
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]
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}
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],
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"display_name": "SageMath 9.5",
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"language": "sage",
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"name": "sagemath"
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},
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"name": "ipython",
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"file_extension": ".py",
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"mimetype": "text/x-python",
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