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@ -7,28 +7,46 @@
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"source": [
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"# [Non-Abundant Sums](https://projecteuler.net/problem=23)\n",
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"\n",
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"Just like in [problem 21](https://projecteuler.net/problem=21), we'll define an `aliquot_sum` function and use that to find all the [abundant numbers](https://en.wikipedia.org/wiki/Abundant_number) below 28,124. Then we check every integer less than 28,124 to see if it's the sum of any two abundant numbers, and if it is, remove it from a set containing all those integers. Whatever's left in that set are the non-abundant sums."
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"Just like in [problem 21](https://projecteuler.net/problem=21), we'll define an `aliquot_sum` function and use that to find all the [abundant numbers](https://en.wikipedia.org/wiki/Abundant_number) below 28,124 (as in problem 21, we could instead use a sieve to compute the divisor sums)."
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]
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},
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{
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"cell_type": "code",
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"execution_count": 1,
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"id": "84f3ad0c",
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"metadata": {},
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"outputs": [],
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"source": [
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"aliquot_sum = lambda n: sigma(n) - n\n",
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"abundant_numbers = {k for k in range(1, 28124) if aliquot_sum(k) > k}"
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]
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},
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{
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"cell_type": "markdown",
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"id": "d6586d17",
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"metadata": {},
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"source": [
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"Then we check every integer less than 28,124 to see if it's the sum of any two abundant numbers, and if it is, remove it from a set containing all those integers. Whatever's left in that set are the non-abundant sums."
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]
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},
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{
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"cell_type": "code",
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"execution_count": 2,
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"id": "6747d2a3",
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"metadata": {},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"4179871\n"
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]
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"data": {
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"text/plain": [
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"4179871"
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]
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},
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"execution_count": 2,
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"metadata": {},
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"output_type": "execute_result"
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}
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],
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"source": [
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"aliquot_sum = lambda n: sigma(n) - n\n",
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"\n",
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"abundant_numbers = {k for k in range(1, 28124) if aliquot_sum(k) > k}\n",
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"\n",
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"non_abundant_sums = set(range(1, 28124))\n",
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"for n in range(1, 28124):\n",
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" for m in abundant_numbers:\n",
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@ -36,7 +54,7 @@
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" non_abundant_sums.discard(n)\n",
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" break\n",
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"\n",
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"print(sum(non_abundant_sums))"
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"sum(non_abundant_sums)"
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]
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},
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{
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